2x^2+155x=25200

Solution for 2x^2+155x=25200 equation:

2x^2+155x=25200

We move all terms to the left:

2x^2+155x-(25200)=0

a = 2; b = 155; c = -25200;
Δ = b2-4ac
Δ = 1552-4·2·(-25200)
Δ = 225625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225625}=475$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(155)-475}{2*2}=\frac{-630}{4}
=-157+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(155)+475}{2*2}=\frac{320}{4}
=80
$